1.

the length of inclined plane at 30°is 20 m and sphere of mass 5 kg start rolling from the rest from the top of the plane if there is 20% loss of kinetic energy due to friction etc. then calculate the velocity of the sphere at the bottom of the plane

Answer»

The change in kinetic energy when the ball reaches the bottom of the plane is 500J loss due to friction =100J (20%of 500J )net change in kinetic energy=400J 1/2×mass of ball×(velocity at base of the plane^2)-1/2×mass of the ball×(velocity at the top of the plane^2)=400J1/2×mass of the ball ×velocity at the base of the plane=400J (because velocity at the top of the plane is 0)1/2×5×(velocity at base ^2)=400Jvelocity at base =4 (root10)



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