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the length of inclined plane at 30°is 20 m and sphere of mass 5 kg start rolling from the rest from the top of the plane if there is 20% loss of kinetic energy due to friction etc. then calculate the velocity of the sphere at the bottom of the plane |
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Answer» The change in kinetic energy when the ball reaches the bottom of the plane is 500J loss due to friction =100J (20%of 500J )net change in kinetic energy=400J 1/2×mass of ball×(velocity at base of the plane^2)-1/2×mass of the ball×(velocity at the top of the plane^2)=400J1/2×mass of the ball ×velocity at the base of the plane=400J (because velocity at the top of the plane is 0)1/2×5×(velocity at base ^2)=400Jvelocity at base =4 (root10) |
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