InterviewSolution
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InterviewSolution
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The length of the wire shown in Fig. Between the pulley and fixed support is `1.5m` and mass is `12.0g` the frequency of vibration with which the wire vibrate two loops leaving the middle point of the wire between the pulleys at rest isA. `10Hz`B. `30Hz`C. `100Hz`D. `70Hz` |
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Answer» Correct Answer - C `f=(2)/(2l)sqrt((T)/(mu))` or `f=(1)/(l)sqrt((T)/(mu))` or `f=sqrt((Tl)/(Ml^(2))` or `f=sqrt((T)/(Ml))` or `v=sqrt((18xx10xx1000)/(12xx1.5))Hz=100Hz`. |
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