1.

the length of wire is increased by 0.1% of its initial length, how many percentage by its resistance will increase​

Answer»

initially,Length=lCross−sectionarea=AResistance=RAfter increase, Length=l′Cross-sectional area=A′RESISTANCE=R′l′=l+0.1%l=l+1000.1l=1.001lBut, volume remains same.V′=V⇒A′l′=Al⇒A′(1001)L=Al∴A′=1.001ANew Resistance(R′)=ρAplease MARK as branliest



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