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The line of action of the resultant of two like parallel forces shifts by one-fourth of the distance between the forces when the two forces are interchanged. The ratio of the two forces is:A. `3:4`B. `1:2`C. `3:5`D. `2:3` |
Answer» Correct Answer - c Let the distance between two parallel forces `F_(1)` and `F_(2)` be `L` if `r_(1)` is distance of the resultant then equating the moments of the forces `F_(1) xx r_(1) = F_(2) xx r_(2)` or `(r_(1))/(r_(2)) = (F_(2))/(F_(1))` Also `r_(1) = (F_(2) L)/(F_(1) + F_(2))` and `r_(2) = (F_(1)L)/(F_(1) + F_(2))` As `r_(1) = r_(2) + (L)/(4)` `:. (F_(2)L)/(F_(1) + F_(2)) = (F_(1)L)/(F_(1) + F_(2)) + (L)/(4)` `(F_(2))/(F_(1) + F_(2)) = (5F_(1) + F_(2))/(4(F_(1) +F_(2))` or `5 F_(1) + F_(2) = 4 F_(2)` `5 F_(1) = 3 F_(2)` or `(F_(1))/(F_(2)) = (3)/(5)` . |
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