The linear density of a vibrating string is `1.3 xx 10^(-4) kg//m` A transverse wave is propagating on the string and is described by the equation `y= 0.021 sin (x + 30 t)` where x and y are measured in meter and t`t` in second the tension in the string is :-A. 0.48 NB. 1.20 NC. 0.117 ND. 4.8 N

The linear density of a vibrating string is `1.3 xx 10^(-4) kg//m` A t

1.	The linear density of a vibrating string is `1.3 xx 10^(-4) kg//m` A transverse wave is propagating on the string and is described by the equation `y= 0.021 sin (x + 30 t)` where x and y are measured in meter and t`t` in second the tension in the string is :-A. 0.48 NB. 1.20 NC. 0.117 ND. 4.8 N
Answer» Correct Answer - C `omega = 30 therefore 2pin = 30 therefore n=(15)/(pi)` `K=1 therefore (2pi)/(lamda) =1 therefore lamda = 2pi` `v=nlamda = (15)/(pi) xx2pi = 30m//s` `v=sqrt(T/m) therefore v^2=T/m` `therefore T=v^2m = 30xx30xx1.3xx10^(-4) = 0.177 N`

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The linear density of a vibrating string is `1.3 xx 10^(-4) kg//m` A transverse wave is propagating on the string and is described by the equation `y= 0.021 sin (x + 30 t)` where x and y are measured in meter and t`t` in second the tension in the string is :-A. 0.48 NB. 1.20 NC. 0.117 ND. 4.8 N

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