1.

The linear momentum of a body changes from 18 kg m/s to 27 kg m/s in three seconds. What is the force acting on body?

Answer»

ANSWER:

Initial velocity (U)=

5

20

=4m/s

Acceleration produced =

m

F

=1m/s

2

FINAL velocity(v)=u+at=4+1(10)=14

So, Change in K.E =

2

1

m(v

2

−u

2

)=

2

1

(5)(196−16)=450J

Therefore, D is correct option.

Explanation:

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