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The linear momentum of a body changes from 18 kg m/s to 27 kg m/s in three seconds. What is the force acting on body? |
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Answer» Initial velocity (U)= 5 20
=4m/s Acceleration produced = m F
=1m/s 2
FINAL velocity(v)=u+at=4+1(10)=14 So, Change in K.E = 2 1
m(v 2 −u 2 )= 2 1
(5)(196−16)=450J Therefore, D is correct option. Explanation: plz mark as brainleast ppz |
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