InterviewSolution
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InterviewSolution
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The magnetic field in a plane electromagnetic wave is given by `B_(y)=2xx10^(-7)sin (0.5xx10^(3)x + 1.5 xx 10^(11) t)T`. What is the wavelength and frequency of the wave ? |
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Answer» Comparing the given equation with `B_(y)=B_(0)sin[2pi((x)/(lambda)+(t)/(T))]` We get , `lambda=(2pi)/(0.5xx10^(3))m=1.26 cm,` and `(1)/(T)=v=(1.5xx10^(11))//2pi=23.9` GHz |
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