1.

. The magnitude of force between two straight parallel current carrying conductors kept at a distance d apart in air isgiven byuo il22 dUse it and convention that force of attraction is negative and repulsion is positive

Answer»

The conductor ‘b’ will experience a sideways force on account of the external field Ba. The direction of this force is towards the conductor ‘a’. you can verify this either by the cross product rule of vectors or by Fleming’s left hand rule. We label this force Fba, the force on a segment L of ‘b’ due to ‘a’. The magnitude of this force is given by,

Fba= iaIBa

FbaL

=

μ0iaib/2πd



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