The mass of a bicycle rider along with the bicycle is 100 kg. he wants to cross over a circular turn of radius 100 m with a speed of `10 ms^(-1)`. If the coefficient of friction between the tyres and the road is 0.6, will the rider be able to cross the turn? Take `g = 10 ms^(-2)`.A. 300NB. 600NC. 1200ND. 150N

The mass of a bicycle rider along with the bicycle is 100 kg. he wants

1.	The mass of a bicycle rider along with the bicycle is 100 kg. he wants to cross over a circular turn of radius 100 m with a speed of `10 ms^(-1)`. If the coefficient of friction between the tyres and the road is 0.6, will the rider be able to cross the turn? Take `g = 10 ms^(-2)`.A. 300NB. 600NC. 1200ND. 150N
Answer» Correct Answer - B Centripetal force `=(mv)^(2)/(r)=(100xx10xx10)/(100)=100N` Required frictional force to cross the turn `=mumg=0.6xx100xx10=600N` As the friciton force is greater than the centripetal force, so the rider will be able to cross the turn.

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