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The mass of a circular ring is `M` and its radius is `R`. Its moment of inertia about an axis in the plane of ring at perpendicular distance `R//2` from centre of ring isA. `(MR^(2))/4`B. `(MR^(2))/2`C. `(3MR^(2))/2`D. `(3MR^(2))/4` |
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Answer» Correct Answer - D `I=I_(C)+md^(2),I_(C)=(MR^(2))/2, d=R/2` |
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