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The mass, specific heat capacity and the temperature of a solid are `1000g,(1)/(2) cal/g - .^(@)C` and `80^(@)C` respectively. The mass of the liquid and the calorimeter are `900g` and `200g`. Initially,both are at room temperature `20^(@)C` Both calorimeter and the solid are made of same material. In the steady state, temperature of mixture is `40^(@)C`, then specific heat capacity of the unknown liquid. |
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Answer» Correct Answer - A::C `m_1`=mass of solid =`1000g,S_1=`Specific heat of solid`=1/2 cal//g-.^(@)C` `=S_2` or specific heat of calorimeter `m_2` = mass of calorimeter `=200g` `m_3` =mass of unknown liquid `= 900g` `S_3` =specific heat of unknown liquid from law of heat exchange, Heat given by solid= Heat taken by calorimeter + Heat taken by unknown liquid `:. m_(1)S_(1)|Delta theta_(1)|=m_(2)S_(2)|Delta theta_(2)|+m_(3)S_(3)|Delta theta_(3)|` `:. 1000xx (1)/(2)xx (80-40)=200xx1/2(40-20)+ 900 xxS_(3)(40-20)` Solving this equation we get, `S_3=1 cal//g-.^(@) C`. |
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