InterviewSolution
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InterviewSolution
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The masses `m_(1) m_(2)` and `m_(3)` of the three bodies shown in fig . Are 5 , 2 and 3 kg respectively Calculate the valuse of tension `T_(1) T_(2)` and `T_(3)` when (i) the whole system is going upward with an acceleration of `2 m//s^(2)` (ii) the whole system is stationary ` (g=9.8 m//s^(2))` . . |
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Answer» All the three bodies are moving together with an an upward acc . Of `2 m//s^(2)` The force pulling the system upwards is `T_(1)` and downward pull of gravity is ` (m_(1) + m_(3)) g` According to Newton s 2 nd law of motion `T_(1) - (m_(1) + m_(2) + m_(3) ) g = (m_(1) + m_(3) ) a` or `T_(1) = (m_(1) + m _(2) + m_(3) ) (a + g )` ` = (5+2+3) (2+9.8) = 118 N ` Similarly , for motion of `m_(2)` and `m_(3)` ., we write `T_(2) = (m_(2) + m_(3) ( a+g ) = (2+3) (2 + 9.8)` `= 590 N` and for motion of `m_(3)` `T_(3) = m_(3) (a+g ) = 3 (2+ 9.8 ) = 35 .4 N` (ii) When the whole system is stationary `a= 0 ` Using the same equations as above with a = 0 , ` T_(1) = (m_(1) + m_(2) + m_(3)) g = 10 xx 9.8 = 98 N` `T_(2) = (m_(2) + m_(3)) g = 5 xx 9.8 = 49 N` `T_(3) = m_(3) xx g = 3 xx 9.8 = 29 . 4 N ` |
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