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The matrix A=\(\begin{bmatrix}0&1&1\\1&0&-1\\-1&1&0\end{bmatrix}\) is symmetric.(a) True(b) FalseThe question was posed to me in a job interview.This intriguing question comes from Symmetric and Skew Symmetric Matrices topic in section Matrices of Mathematics – Class 12

Answer»

Right OPTION is (B) False

To EXPLAIN: GIVEN that, A=\(\begin{bmatrix}0&1&1\\1&0&-1\\-1&1&0\end{bmatrix}\)

⇒A’=\(\begin{bmatrix}0&1&-1\\1&0&1\\1&-1&0\end{bmatrix}\). ∴A ≠ A’. Hence, it is not symmetric.



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