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The maximum kinetic energy of a photoelectron is 3 eV. What is the stopping potential?(a) 0 V(b) 3 V(c) 9 V(d) 12 VThe question was asked in unit test.My doubt stems from Einstein’s Photoelectric Equation : Energy Quantum of Radiation topic in section Dual Nature of Radiation and Matter of Physics – Class 12

Answer»

Right ANSWER is (B) 3 V

For explanation I would say: Stopping potential is given as:

V0 = \(\frac {K_{max}}{E}\)

V0 = \(\frac {3eV}{e}\)

V0 = 3 V

Therefore, the stopping potential is 3 V.



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