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The mechanism of the reaction `A+2B rarr C+D` is: Step I: `A+B underset(k_(2))overset(k_(1))hArr I` Step II: `B+I overset(k_(3))rarr C+D` In the first step is a fast equilibruim , then the incorrect statement is :A. Order of reacton with respect to A is 1.B. Order of reacton with respect to B is 2.C. Overall rate of reaction is ,`r=K_(3).[A][B]^(2)`D. Rates of forward and backward reaction of step I is much greater than the rate of reaction of step II. |
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Answer» Correct Answer - C |
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