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the minute hand of a wall clock is 10 cm long find its displacement and the distance covered from 10 a.m. to 10:45 a.m. |
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Answer» Answer: DISTANCE = 47.1CM , DISPLACEMENT = 35.7CM Explanation: Here R=10cm Let's break it into two parts, From 10 am to 10.30 am minute HAND rotates 180° from 0 minute to 30 minutes. Hence distance covered is half the circle means semi circle. distance= perimeter of semi circle distance(1) = πR = 3.14×10= 31.4 cm now 1/4th of circle covers distance 10.30AM to 10.45 AM i.e. 90 degree. SO, distance(2) = πr/2 = 31.4/2 = 15.7cm Total distance = 31.4+15.7 = 47.1cm Displacement is shortest distance between two points. i.e. distance between 10.00 and 10.45 in clock wise direction. displacement is twice the length of the hand Displacement= 2×r= 2× 10= 20cm 1/4 distance between 10.30 to 10.45 = 15.7cm total displacement, = 20+15.7cm = 35.7cm I HAVE JUST TRIED TO ANSWER THE QUESTION TO MY BEST. MUST COMMENT ME FOR ANY ERROR YOU FOUND IN ANSWER AS I WANT TO KNOW MY MISTAKE.PLZ LIKE AND MARK MY ANSWER AS BRAINLIEST IF YOU FOUND MY ANSWER HELPFUL. |
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