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The molar heat of formation of `NH_(4)NO_(3)(s)` is `-367.54 kJ ` and those of `N_(2)O(g)`and `H_(2)O(l) ` are `+ 81.46kJ ` and `- 285.78 kJ` respectively at `25^(@)C`and 1.0 atmospheric pressure. Calculate `DeltaH ` and `Delta U` for the reaction `NH_(4)NO_(3)(s) rarr N_(2)O(g) + 2H_(2)O(l)` |
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Answer» Correct Answer - `DeltaH = -122.56;Delta U = - 125. -4 kJ ` `DeltaH_("reaction") =Sigma Delta_(f) H (` Products ) `- Sigma Delta_(f) H(` Reactants) `Deltan_(g) = n_(p) - n_(r) = 1-0 = 1 ` ` Delta U = Delta H - Delta n_(g)RT` |
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