1.

The molar specific heat of He at constant volume is 12.47 J/mol.K. Two moles of He are heated at constant pressure so that the rise in temperature is 10 K. Find the increase in the internal energy of the gas.

Answer»

Data : Cv = 12.47 J/mol.k, n = 2, Tf – Ti = 10 K 

The increase in the internal energy of the gas,

∆ U = nCv (Tf – Ti)

= (2) (12.47) (10) J 

= 249.4 J



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