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The molar specific heat of He at constant volume is 12.47 J/mol.K. Two moles of He are heated at constant pressure so that the rise in temperature is 10 K. Find the increase in the internal energy of the gas. |
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Answer» Data : Cv = 12.47 J/mol.k, n = 2, Tf – Ti = 10 K The increase in the internal energy of the gas, ∆ U = nCv (Tf – Ti) = (2) (12.47) (10) J = 249.4 J |
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