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The moment of inertia of a disc of mass `M` and radius `R` about an axis. Which is tangential to sircumference of disc and parallel to its diameter is. |
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Answer» About the tangent parallel to the diameter `I=I_(g)+MR^(2)=(MR^(2))/4+MR^(2)=5/4 MR^(2)` |
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