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The moment of inertia of a solid cylinder about its natural axis is `I`. If its moment of inertia about an axis `bot^r` to natural axis of cylinder and passing through one end of cylinder is `191//6` then the ratio of radius of cylinder and its length isA. `1:2`B. `1:3`C. `1:4`D. `2:3` |
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Answer» Correct Answer - A `I=(MR^(2))/2,I_(1)=(19I)/6=(ML^(2))+(MR^(2))/4` |
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