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The moment of inertia of a then circular disc about an axis passing through its centre and perpendicular to its plane is `I`. Then, the moment of inertia of the disc about an axis parallel to its diameter and touching the edge of the rim is |
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Answer» `I=(MR^(2))/2rArrMR^(2)=2I` `M.I.` of the disc about tangent in a plane `=5/4MR^(2)=5/2 I` |
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