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The moment of inertia of a thin square plate of mass `1.2 kg ` is `0.2 kg m^(2)` when its is made to rotate about an axis perpendicular to plane of plate and through a corner of plate. The side length of plate isA. `0.2 m`B. `0.4m`C. `0.5 m`D. `0.8m` |
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Answer» Correct Answer - C `I=(MR^(2))/6+M(L/(sqrt(2)))^(2)=0.2` |
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