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The moment of inertia of a wheel of radius `20 cm` is `40 kgm^(2)` if a tangential force of `80 N` applied on the wheel, its rotational `K.E.` after `4s` isA. `16.2J`B. `51.2J`C. `25.6 J`D. `24.8J` |
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Answer» Correct Answer - B `omega=omega_(0)+alphat, KE=1/2Iomega^(2)` |
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