The most probable velocity of a gas is proportional to(A) T(B) VTIC 12

1.	The most probable velocity of a gas is proportional to(A) T(B) VTIC 12(D) 13/2
Answer» $\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}}$ => The most probable velocity(VMP) of a gas molecule is given by... $\: \: \: \: \: \green{ \huge{ \star}} \: \: \boxed{ \huge \pink{Vmp = \sqrt{ \frac{2 \times <klux>KB</klux> \times T}{m} } }} \: \: \green {\huge{ \star}}$ => here, Kb = boltzman constant T = trmperature m = mass of a single molecule => as PER the given formula it is CLEAR that $\orange{ \huge{\implies}} \: \: \boxed{ \boxed{ \blue{ \bold{ \huge{ \underline{ \mathfrak{Vmp \propto \: \sqrt{T}}}}}}}}$

The most probable velocity of a gas is proportional to(A) T(B) VTIC 12(D) 13/2

Answer»

$\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}}$

=> The most probable velocity(VMP) of a gas molecule is given by...

$\: \: \: \: \: \green{ \huge{ \star}} \: \: \boxed{ \huge \pink{Vmp = \sqrt{ \frac{2 \times <klux>KB</klux> \times T}{m} } }} \: \: \green {\huge{ \star}}$

=> here, Kb = boltzman constant

T = trmperature

m = mass of a single molecule

=> as PER the given formula it is CLEAR that

$\orange{ \huge{\implies}} \: \: \boxed{ \boxed{ \blue{ \bold{ \huge{ \underline{ \mathfrak{Vmp \propto \: \sqrt{T}}}}}}}}$

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