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the motor cycle after 10 seconds, and the distance travelled in this time.Ans: Tn . com029. The brakes applied to a car produce an acceleration of m/s in the opposite direction to the motion. If thecar takes 2 sec to stop alter the application of brakes, calculate the distance it travels during this time. Ans: 12-a walito km/h in 5 minutes. Assuming that the acceleration is |
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Answer» Acceleration a = -6 m/s^2Time t = 2 sFinal velocity v = 0 m/s Let initial velocity be uLet distance be s v = u + atSo, 0 = u + (-6)(2)So, u = 12 m/s Now, s = ut + (1/2) at^2So, s = 12(2) + (1/2)(-6)(2^2)So, s = 24 - 12So, s = 12 m Thus, distance travelled is 12 m |
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