The nth term of an A.P., the sum of whose n terms is Sn, is A. Sn + S

1.	The nth term of an A.P., the sum of whose n terms is Sn, is A. Sn + Sn–1 B. Sn – Sn–1 C. Sn + Sn + 1 D. Sn – Sn + 1
Answer» The sum of n terms of an A.P is given by S_n S_n = \(\frac{n}{2}\)(2a + (n–1) d) If the sum of n terms is given that is S_n is given then the nth term is given by the formula T_n = S_n– S_n–1 Where S_n–1 is sum of the (n–1)^th term of the A.P.

The nth term of an A.P., the sum of whose n terms is Sn, is A. Sn + Sn–1 B. Sn – Sn–1 C. Sn + Sn + 1 D. Sn – Sn + 1

Answer»

The sum of n terms of an A.P is given by S_n

S_n = \(\frac{n}{2}\)(2a + (n–1) d)

If the sum of n terms is given that is S_n is given then the nth term is given by the formula

T_n = S_n– S_n–1 Where S_n–1 is sum of the (n–1)^th term of the A.P.