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The number of neutrons emitted when `._(92)^(235)U` undergoes controlled nuclear fission to `._(54)^(142)Xe` and `._(38)^(90)Sr ` is |
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Answer» Correct Answer - 4 `._(92)^(235)U+._(0)n^(1) rarr ._(54)^(142) Xe+._(38)^(142)Xe+._(38)^(90)Sr+x ._(0)n^(1)` Applying mass number balance `235+1=142+90+x` `x=4` |
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