The number of possible global alignments between two sequences of length N is _____(a) (frac{2^N}{sqrt{πN}})(b) (frac{2^{2N}}{sqrt{πN}})(c) (frac{2^{(N-1)}}{sqrt{πN}})(d) (frac{2^{2N}}{sqrt{N}})

The number of possible global alignments between two sequences of leng

1.	The number of possible global alignments between two sequences of length N is _____(a) (frac{2^N}{sqrt{πN}})(b) (frac{2^{2N}}{sqrt{πN}})(c) (frac{2^{(N-1)}}{sqrt{πN}})(d) (frac{2^{2N}}{sqrt{N}})
Answer» Right choice is (b) (frac{2^{2N}}{sqrt{πN}}) For explanation I would say: By the total number of permutations and combinations option b gives the accurate number of possible global alignments between two sequences of length N. For two sequences of 250 residues this is 10^149.

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The number of possible global alignments between two sequences of length N is _____(a) (frac{2^N}{sqrt{πN}})(b) (frac{2^{2N}}{sqrt{πN}})(c) (frac{2^{(N-1)}}{sqrt{πN}})(d) (frac{2^{2N}}{sqrt{N}})

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