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The number of real solution of equation `tan^(-1)x+cot^(-1)(-|x|)=2tan^(-1)(6x)` isA. 4B. 3C. 2D. 1 |
Answer» Correct Answer - C When x lt 0, wwe have `tan^(-1)(6x)=(pi)/(4)` `rArr x =(1)/(6)`, which is not possible When `x ge 0`, we have `(pi)/(4)=tan^(-1)(6x)-tan^(-1)(x)` `rArr (6x-x)/(1+6x^(2))=1` `rArr x=(1)/(2),(1)/(3)` |
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