1.

The number of real solutions of the equation `sin(e^x)=2^x+2^(-x)` is

Answer» Correct Answer - A
We known that
`AM geGM`
`:. (2^(x)+2^(-x))/(2)gesqrt(2^(x)xx2^(-x))`
`implies 2^(x)+2^(-x)ge2`
But, `sin(e^(x)) le1`.
Thus, `sin(e^(x)) ne 2^(x)+2^(-x)` for any `x in R`
Hence, the given equation has no solution.


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