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The number of real solutions of the equation `sin(e^x)=2^x+2^(-x)` is |
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Answer» Correct Answer - A We known that `AM geGM` `:. (2^(x)+2^(-x))/(2)gesqrt(2^(x)xx2^(-x))` `implies 2^(x)+2^(-x)ge2` But, `sin(e^(x)) le1`. Thus, `sin(e^(x)) ne 2^(x)+2^(-x)` for any `x in R` Hence, the given equation has no solution. |
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