1.

The equation `||x-2|+a|=4`can have four distinct real solutions for `x`if `a`belongs to the interval`(-oo,-4)`(b) `(-oo,0)``(4,oo)`(d) none of theseA. `(-oo,4)`B. `(-oo,-4)`C. `(4,oo)`D. `[-4,4]`

Answer» Correct Answer - B
`||x-1|+a|=4`
`implies|x-1|+a=+-4`
`implies|x-1|=+-a`
For real solutions, we must have
`+-4-a gt 0`
`implies 4-a ge0` and `-4-a ge0`
`ale4` and `a le-4`
`implies ale-4 implies ale4 implies a in(-oo,-4]`


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