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The equation `||x-2|+a|=4`can have four distinct real solutions for `x`if `a`belongs to the interval`(-oo,-4)`(b) `(-oo,0)``(4,oo)`(d) none of theseA. `(-oo,4)`B. `(-oo,-4)`C. `(4,oo)`D. `[-4,4]` |
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Answer» Correct Answer - B `||x-1|+a|=4` `implies|x-1|+a=+-4` `implies|x-1|=+-a` For real solutions, we must have `+-4-a gt 0` `implies 4-a ge0` and `-4-a ge0` `ale4` and `a le-4` `implies ale-4 implies ale4 implies a in(-oo,-4]` |
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