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The number of values of x where the function `f(x)=cos x +cos (sqrt(2)x)` attains its maximum value is |
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Answer» `f(x) = cos x+ cos ( sqrt2 x)` `x=0 => f(x)_(max) = 2` `T(cos x) = 2 pi` `T ( cos sqrt2 x) = ( 2 pi)/ sqrt2 = sqrt 2 pi` so `2x = 2n pi` `x= n pi` `sqrt2 x = 2m pi` `x = sqrt2 m pi` So option 2 is correct Answer |
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