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The number of ways in which a host lady invite 8 people for a party of 8 out of 12 people of whom two do not want to attend the party together is (a) 2 × 11C7 + 10C8 (b) 11C7 + 10C8 (c) 12C8 – 10C6(d) 10C6 + 2! |
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Answer» (c) 12C8 – 10C6 Number of way of selecting 8 people from 12 in 12C8 ∴ out of remaining people 8 can attend in 10C8 The number of ways in which two of them do not attend together = 12C8 – 10C6 |
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