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The outer face of a rectangular slab of equal thickness of iron and brass are maintained at `100^(@)C` and `0^(@)C`, respectively. Find the temperature of the interface. The conductivities of iron and brass are 14 and `126 Wm^(-1) K^(-1)` respectively. |
Answer» Correct Answer - `[10^(@)C]` If T is temperature of the interface of iron and brass slabs, then `(dQ)/(dt)=K_(1)(A(100-T))/(Delta x) =(K_(B)A(T-0))/(Delta x)` or `K_(1)(100-T)=K_(B)T` or `(100-T)/(T)=(K_(B))/(K_(1))=(126)/(14)=9` or `T=10^(@)C` |
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