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The outer radius and the inner radius of a 30 cm long cylindrical gold pipe are 14 cm and 7 cm respectively. It is filled with bronze. The densities of gold and bronze are 20gm/`cm^(3)` and 30gm/`cm^(3)` respectively. Find the weight of the cylinder formed. (in gm)A. `66150pi`B. `99225pi`C. `132300pi`D. `198450pi` |
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Answer» Correct Answer - C Volume of the pipe `=pi (14^(2)-7^(2))(30)cm^(3)` ` :. " Volume of the gold "=pi (14^(2)-7^(2))(30)cm^(3)` Volume of the bronze in the pipe `=pi (7)^(2)(30) cm^(3)` Weight of the pipe (in gms) = Weight of gold in it (in gm) + Weight of bronze in it (in gm) `=[pi (14^(2)-7^(2))(30)][20]+[pi(7)^(2)(30)][30]` `=30pi[(196-49)(20)+(49)(30)]` `=30pi [2940 + 1470]=132300 pi gm.` |
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