1.

The percentage error in the mass and speedare 2% an 3% respectively. What is themaximum error in kinetic energy.Calculated using these quantities

Answer»

KE= 1/2.m.v^2log KE = log 1/2 + log m + 2logvdifferentiating,delta(KE)/KE = delta (m)/m + 2.delta v/vbut given.... [delta m/m=2/100] and [delta v/v=3/100]putting the value we get.delta KE/KE= 8/100% error(max)= [ delta KE/KE ].100 = 8% (ANS)



Discussion

No Comment Found

Related InterviewSolutions