InterviewSolution
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InterviewSolution
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The period of `cosx^2` is |
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Answer» A function is periodic if `f(x) = f(x+T)`. Let us assume that `cos(x^2)` has a period of T. In that case: `cos(x+T)^2 = cosx^2` `=>(x+T)^2 = 2npi+x^2` `=>x^2+T^2+2xT= 2npi+x^2` `=>T^2+2xT-2npi = 0` As we can see, `T` is dependent on the value of `x` and hence, is not a constant. So `cos(x^2)` is not periodic. So, we can say that period of `cosx^2` does not exist. |
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