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The period of oscillation of a simple pendulum in the experiment is recorded as `2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s`. Find the average absolute error.A. 0.1 sB. 0.11 sC. 0.01 sD. 1.0 s |
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Answer» Correct Answer - B Average time period `=(2.63+2.56+2.42+2.71+2.80)/(5)` `(13.12)/(5)=1.624=2.62s` Average absoulte error `=(0.01+0.06+0.20+0.09+0.18)/(5)=(0.54)/(5)` `=0.108=0.11s`. |
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