The period of oscillation of a simple pendulum is `T = 2pisqrt(L//g)`. Measured value of L is `20.0 cm` known to `1mm` accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?A. 0.01B. 0.05C. 0.02D. 0.03

The period of oscillation of a simple pendulum is `T = 2pisqrt(L//g)`.

1.	The period of oscillation of a simple pendulum is `T = 2pisqrt(L//g)`. Measured value of L is `20.0 cm` known to `1mm` accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?A. 0.01B. 0.05C. 0.02D. 0.03
Answer» Correct Answer - D `d_(1)=0.5+8xx0.01+0.03` `d_(2)=0.5+4xx0.01+0.03` `d_(3)=0.5+6xx0.01+0.03` `d_(n)=(d_(1)+d_(2)+d_(3))/(3)=0.5+0.03+(18xx0.01)/(3)` `-0.59`

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