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The `pH` of `0.5 M` aqueous solution of `HF` `(K_(a)=2xx10^(-4))` isA. `2`B. `4`C. `6`D. `10`

Answer» Correct Answer - A
`[H^(+)]=sqrt(CK_(a)) =sqrt(0.5xx2xx10^(-4))=10^(-2) M`
`pH= -log 10 [H^(+)]= -log 10^(-2)=2`


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