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The `pH` of `0.5 M` aqueous solution of `HF` `(K_(a)=2xx10^(-4))` isA. `2`B. `4`C. `6`D. `10` |
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Answer» Correct Answer - A `[H^(+)]=sqrt(CK_(a)) =sqrt(0.5xx2xx10^(-4))=10^(-2) M` `pH= -log 10 [H^(+)]= -log 10^(-2)=2` |
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