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The `pH` of `Ba(OH)_(2)` solution is `13`. The number millimoles of `Ba(OH)_(2)` present in `10 ml` of solution would beA. `1.00`B. `0.50`C. `10.00`D. `15.00` |
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Answer» Correct Answer - B `[OH^(-)]=0.1` and conc. of `Ba(OH)_(2)=(0.1)/(2)` `:.` The no. of milimoles of `Ba(OH)_(2)` present in `10 ml` soultion `=(0.1)/(2)xx10xx10^(-3)xx10^(3)=0.5` |
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