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The point on the curve `x^2=2y`which is nearest to the point (0, 5) is(A) `(2sqrt(2),4)` (B) `(2sqrt(2),0)` (C) (0, 0) (D) (2, 2) |
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Answer» If we see the options, option - `(B)` do not satisfy the equation of the curve. So, it is not the answer. Now, we will calculate the distance of rest of three options from `(0,5)`. For Option - (A), `d = sqrt((2sqrt2-0)^2+(4-5)^2) = 3` For Option - (C), `d = sqrt((0-0)^2+(0-5)^2) = 5` For Option - (D), `d = sqrt((2-0)^2+(2-5)^2) = sqrt13` As, `d` in case of option - (A) is the minimum, so `(2sqrt2,4)` is the nearest point. |
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