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The point `P` of a string is pulled up with an acceleration `g`. Then the acceleration of the hanging disc (w.r.t ground) over which the string is wrapped, is A. `(2 g)/3 darr`B. `g/3 uarr`C. `(4g)/3 darr`D. `g/3 darr` |
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Answer» Correct Answer - D `2mg-T=ma, TR=Ialpha` `alpha=a/R,`solving `alpha=g/3` |
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