The points `(-a,-b)`, `(0,0)`. `(a,b)` and `(a^(2),ab))` areA. collinearB. vertices of a rectangleC. vertices of a parallelogramD. None of the above

The points `(-a,-b)`, `(0,0)`. `(a,b)` and `(a^(2),ab))` areA. colline

1.	The points `(-a,-b)`, `(0,0)`. `(a,b)` and `(a^(2),ab))` areA. collinearB. vertices of a rectangleC. vertices of a parallelogramD. None of the above
Answer» The point `O(0,0)` is the mid-point of `A(-a,-b)` and `B(a,b)`. Therefore, `A,O,B` are collinear and equation of line `AOB` is `y=(b)/(a)x` Since, the fourth point `D(a^(2),ab)` satisfies the above equation. Hence, the four points are collinear.

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The points `(-a,-b)`, `(0,0)`. `(a,b)` and `(a^(2),ab))` areA. collinearB. vertices of a rectangleC. vertices of a parallelogramD. None of the above

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