The population of a certain city was 72000 on the last day of the year

1.	The population of a certain city was 72000 on the last day of the year 1998. During next year it increased by 7% but due to an epidemic it decreased by 10% in the following year. What was its population at the end of the year 2000?
Answer» Given, Population of city on last day of year 1998 = 72000 Increasing rate in 1999 = 7% Decreasing rate in 2000 = 10 % So, Population at the end of 2000 \(= 72000\times({1}+\frac{7}{100})({1}-\frac{10}{100})\) \(= 72000\times\frac{107}{100}\times\frac{9}{10}\) = 69336.

The population of a certain city was 72000 on the last day of the year 1998. During next year it increased by 7% but due to an epidemic it decreased by 10% in the following year. What was its population at the end of the year 2000?

Answer»

Given,

Population of city on last day of year 1998 = 72000

Increasing rate in 1999 = 7%

Decreasing rate in 2000 = 10 %

So,

Population at the end of 2000 \(= 72000\times({1}+\frac{7}{100})({1}-\frac{10}{100})\)

\(= 72000\times\frac{107}{100}\times\frac{9}{10}\) = 69336.