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The population of a city increases at the rate of 4% per annum. There is additional annual increase of 1% due to influx of job seekers. The % increase in the population after 2 years is (a) 10 (b) 10.25 (c) 10.5 (d) 10.75 |
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Answer» (b) 10.25 Let the population of the city be 100. Then Population of city after 2 years = 100\(\big(1+\frac{5}{100}\big)^2\) = 100 x \(\frac{21}{20}\) x \(\frac{21}{20}\) = 110.25 \(\therefore\) Increase per hundred in 2 years = 110.25 – 100 = 10.25% |
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