1.

The population of a town increases by 5% annually. If the population in 2009 is 1,38,915 what was it in 2006 ?

Answer»

Let the population in 2006 be x.

Pop. in 2009 = x x \(\big(1+\frac{5}{100}\big)^3\)

\(\Rightarrow\) 1,38,915 = x x \(\big(\frac{21}{20}\big)^3\)

\(\Rightarrow\) x = \(\frac{138915\times 8000}{9261}\) = 120000


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