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The population of a town was 1,60,000 three years ago. If it increased by 3%, 2.5% and 5% respectively in the last three years, then what is the present population ? |
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Answer» Present population = 1,60,000\(\big(1+\frac{3}{100}\big)\big(1+\frac{2.5}{100}\big)\big(1+\frac{5}{100}\big)\) = 160000 x \(\frac{103}{100}\) x \(\frac{102.5}{100}\) x \(\frac{105}{100}\) = 177366. |
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