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The position vectors of the points A, B, C are `2 hati + hatj - hatk , 3 hati - 2 hatj + hatk and hati + 4hatj - 3 hatk ` respectively . These pointsA. form an isosceles triangleB. form a right angled triangleC. are collinearD. form a scalene triangle |
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Answer» Correct Answer - C `AB=(3-2)hati+(-2-1)hatj+(1+1)hatk` `=hati-3hatj+2hatk` `BC=(1-3)hati+(4+2)hatj+(-3-1)hatk` `=-2hati+6hatj-4hatk` `CA=(2-1)hati+(1-4)hatj+(-1+3)hatk` `=hati-3hatj-2hatk` `|AB|=sqrt(1+9+4)=sqrt(24)` `|BC|=sqrt(4+36+16)=sqrt(56)=2sqrt(14)` `|CA|=sqrt(1+9+4)=sqrt(24)` So, `|AB|+|AC|=|BC|` and angle between AB and BC is `180^(@)` so, points A,B and C cannot form an isosceles triangle. Hence, A,B and C are collinear. |
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