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The position x of a particle of mass 2 kg dependson time t (in second) as x(4 +3f-t+ 5) mThe magnitude of force acting on the particleatt=Isis(1) 20 N(2) 30 N(3) 60(4) 90 N |
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Answer» we know that d^2x/dt^2= acceralation where x is displacementso Acceralation = first time diffrentiation= 12t^2+6t-1+0second time = 24t+6t= 130F= ma2*30= 60NAnswerHIT THE LIKE BUTTON IF YOU ARE SATISFIED |
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